Theory Subresultants.Binary_Exponentiation
section ‹Binary Exponentiation›
text ‹This theory defines the standard algorithm for binary exponentiation, or
exponentiation by squaring.›
theory Binary_Exponentiation
imports
Main
begin
declare Euclidean_Rings.divmod_nat_def[termination_simp]
context monoid_mult
begin
fun binary_power :: "'a ⇒ nat ⇒ 'a" where
"binary_power x n = (if n = 0 then 1 else
let (d,r) = Euclidean_Rings.divmod_nat n 2;
rec = binary_power (x * x) d in
if r = 0 then rec else rec * x)"
lemma binary_power[simp]: "binary_power = (^)"
proof (intro ext)
fix x n
show "binary_power x n = x ^ n"
proof (induct x n rule: binary_power.induct)
case (1 x n)
show ?case
proof (cases "n = 0")
case False
note IH = 1[OF False]
obtain d r where n2: "Euclidean_Rings.divmod_nat n 2 = (d,r)" by force
from Euclidean_Rings.divmod_nat_def[of n 2] n2 have dr: "d = n div 2" "r = n mod 2" by auto
hence r: "r = 0 ∨ r = 1" by auto
let ?rec = "binary_power (x * x) d"
have "binary_power x n = (if r = 0 then ?rec else ?rec * x)"
unfolding binary_power.simps[of x n] n2 using False by auto
also have "… = ?rec * x ^ r" using r by (cases "r = 0", auto)
also have "?rec = (x * x) ^ d"
by (rule IH[OF _ refl], simp add: n2)
also have "… = x ^ (d + d)" unfolding power_add
using power2_eq_square power_even_eq power_mult by auto
also have "… * x ^ r = x ^ (d + d + r)"
by (simp add: power_add)
also have "d + d + r = n" unfolding dr by presburger
finally show ?thesis .
qed auto
qed
qed
lemma binary_power_code_unfold[code_unfold]: "(^) = binary_power"
by simp
declare binary_power.simps[simp del]
end
end