Theory Sorts
section ‹Sorts›
text ‹GenRel is a 2-sorted first-order logic. This theory introduces the two sorts and
proves a number of basic arithmetical results. The two sorts are Bodies
(things that can move) and Quantities (used to specify coordinates, masses, etc).›
theory Sorts
imports Main
begin
subsection ‹Bodies›
text ‹There are two types of Body: photons and observers. We do not assume
a priori that these sorts are disjoint.›
record Body =
Ph :: "bool"
Ob :: "bool"
subsection ‹Quantities›
text ‹The quantities are assumed to form a linearly ordered field. We may
sometimes need to assume that the field is also Euclidean, i.e. that
square roots exist, but this is not a general requirement so it
will be added later using a separate axiom class, AxEField.
›
class Quantities = linordered_field
begin
abbreviation inRangeOO :: "'a ⇒ 'a ⇒ 'a ⇒ bool" (‹_ < _ < _›)
where "(a < b < c) ≡ (a < b) ∧ (b < c)"
abbreviation inRangeOC :: "'a ⇒ 'a ⇒ 'a ⇒ bool" (‹_ < _ ≤ _›)
where "(a < b ≤ c) ≡ (a < b) ∧ (b ≤ c)"
abbreviation inRangeCO :: "'a ⇒ 'a ⇒ 'a ⇒ bool" (‹_ ≤ _ < _›)
where "(a ≤ b < c) ≡ (a ≤ b) ∧ (b < c)"
abbreviation inRangeCC :: "'a ⇒ 'a ⇒ 'a ⇒ bool" (‹_ ≤ _ ≤ _›)
where "(a ≤ b ≤ c) ≡ (a ≤ b) ∧ (b ≤ c)"
lemma lemLEPlus: "a ≤ b + c ⟶ c ≥ a - b"
by (simp add: add_commute local.diff_le_eq)
lemma lemMultPosLT1:
assumes "(a > 0) ∧ (b ≥ 0) ∧ (b < 1)"
shows "(a * b) < a"
using assms local.mult_less_cancel_left2 local.not_less by auto
lemma lemAbsRange: "e > 0 ⟶ ((a-e) < b < (a+e)) ⟷ (abs (b-a) < e)"
by (simp add: local.abs_diff_less_iff)
lemma lemAbsNeg: "abs x = abs (-x)"
by simp
lemma lemAbsNegNeg: "abs (-a-b) = abs (a+b)"
using add_commute local.abs_minus_commute by auto
lemma lemGENZGT: "(x ≥ 0) ∧ (x ≠ 0) ⟶ x > 0"
by auto
lemma lemLENZLT: "(x ≤ 0) ∧ (x ≠ 0) ⟶ x < 0"
by force
lemma lemSumOfNonNegAndPos: "x ≥ 0 ∧ y > 0 ⟶ x+y > 0"
by (simp add: local.add_strict_increasing2)
lemma lemSumOfTwoHalves: "x = x/2 + x/2"
using mult_2[of "x/2"] by force
lemma lemDiffDiffAdd: "(b-a)+(c-b) = (c-a)"
by (auto simp add: field_simps)
lemma lemSumDiffCancelMiddle: "(a - b) + (b - c) = (a - c)"
by (auto simp add: field_simps)
lemma lemDiffSumCancelMiddle: "(a - b) + (b + c) = (a + c)"
by (auto simp add: field_simps)
lemma lemMultPosLT: "((0 < a) ∧ (b < c)) ⟶ (a*b < a*c)"
using mult_strict_left_mono by auto
lemma lemMultPosLE: "((0 < a) ∧ (b ≤ c)) ⟶ (a*b ≤ a*c)"
using mult_left_mono by auto
lemma lemNonNegLT: "((0 ≤ a) ∧ (b < c)) ⟶ (a*b ≤ a*c)"
using mult_left_mono by auto
lemma lemMultNonNegLE: "((0 ≤ a) ∧ (b ≤ c)) ⟶ (a*b ≤ a*c)"
using mult_left_mono by auto
abbreviation sqr :: "'a ⇒ 'a"
where "sqr x ≡ x*x"
abbreviation hasRoot :: "'a ⇒ bool"
where "hasRoot x ≡ ∃ r . x = sqr r"
abbreviation isNonNegRoot :: "'a ⇒ 'a ⇒ bool"
where "isNonNegRoot x r ≡ (r ≥ 0) ∧ (x = sqr r)"
abbreviation hasUniqueRoot :: "'a ⇒ bool"
where "hasUniqueRoot x ≡ ∃! r . isNonNegRoot x r"
abbreviation sqrt :: "'a ⇒ 'a"
where "sqrt x ≡ THE r . isNonNegRoot x r"
lemma lemAbsIsRootOfSquare: "isNonNegRoot (sqr x) (abs x)"
by simp
lemma lemSqrt:
assumes "hasRoot x"
shows "hasUniqueRoot x"
proof -
obtain r where "x = sqr r" using assms(1) by auto
define rt where "rt = (if (r ≥ 0) then r else (-r))"
hence rt: "rt ≥ 0 ∧ sqr rt = x" using rt_def ‹x = sqr r› by auto
hence rtroot: "isNonNegRoot x rt" by auto
{ fix y
assume yprops: "isNonNegRoot x y"
hence "y = rt"
using local.square_eq_iff rt by auto
hence "(( y ≥ 0) ∧ (x = sqr y)) ⟶ (y = rt)" by auto
}
hence rtunique: "∀ y . isNonNegRoot x y ⟶ (y = rt)" by auto
thus ?thesis using rtroot by auto
qed
lemma lemSqrMonoStrict: assumes "(0 ≤ u) ∧ (u < v)"
shows "(sqr u) < (sqr v)"
proof -
have 1: "(u*u) ≤ (u*v)" using assms comm_mult_left_mono by auto
have "(u*v) < (v*v)"
using assms mult_commute comm_mult_strict_left_mono by auto
thus ?thesis using 1 le_less_trans by auto
qed
lemma lemSqrMono: "(0 ≤ u) ∧ (u ≤ v) ⟶ (sqr u) ≤ (sqr v)"
by (simp add: local.mult_mono')
lemma lemSqrOrderedStrict: "(v > 0) ∧ (sqr u < sqr v) ⟶ (u < v)"
using mult_mono[of "v" "u" "v" "u"] by force
lemma lemSqrOrdered: "(v ≥ 0) ∧ (sqr u ≤ sqr v) ⟶ (u ≤ v)"
using mult_strict_mono[of "v" "u" "v" "u"] by force
lemma lemSquaredNegative: "sqr x = sqr (-x)"
by auto
lemma lemSqrDiffSymmetrical: "sqr (x - y) = sqr (y - x)"
using lemSquaredNegative[of "y-x"] by auto
lemma lemSquaresPositive: "x ≠ 0 ⟶ sqr x > 0"
by (simp add: lemGENZGT)
lemma lemZeroRoot: "(sqr x = 0) ⟷ (x = 0)"
by simp
lemma lemSqrMult: "sqr (a * b) = (sqr a) * (sqr b)"
using mult_commute mult_assoc by simp
lemma lemEqualSquares: "sqr u = sqr v ⟶ abs u = abs v"
by (metis local.abs_mult_less local.abs_mult_self_eq local.not_less_iff_gr_or_eq)
lemma lemSqrtOfSquare:
assumes "b = sqr a"
shows "sqrt b = abs a"
proof -
have "b ≥ 0" using assms by auto
hence conj1: "hasUniqueRoot b" using lemSqrt[of "b"] assms by auto
moreover have "isNonNegRoot b (abs a)" using lemAbsIsRootOfSquare assms by auto
ultimately have "sqrt b = abs a"
using theI[of "λ r . 0 ≤ r ∧ b = sqr r" "abs a"] by blast
thus ?thesis by auto
qed
lemma lemSquareOfSqrt:
assumes "hasRoot b"
and "a = sqrt b"
shows "sqr a = b"
proof -
obtain r where r: "isNonNegRoot b r" using assms(1) lemSqrt[of "b"] by auto
hence "∀x. 0 ≤ x ∧ b = sqr x ⟶ x = r" using lemSqrt by blast
hence "a = r" using r assms(2) the_equality[of "isNonNegRoot b" "r"] by blast
thus ?thesis using r by auto
qed
lemma lemSqrt1: "sqrt 1 = 1"
proof -
have "isNonNegRoot 1 1" by auto
moreover have "∀ r . isNonNegRoot 1 r ⟶ r = 1"
proof -
{ fix r assume "isNonNegRoot 1 r"
hence r: "(r ≥ 0) ∧ (1 = sqr r)" by simp
hence "r = 1" using calculation lemSqrt by blast
}
thus ?thesis by blast
qed
ultimately show ?thesis using the_equality[of "isNonNegRoot 1" "1"] by blast
qed
lemma lemSqrt0: "sqrt 0 = 0"
using lemZeroRoot local.mult_cancel_right1 by blast
lemma lemSqrSum: "sqr (x + y) = (x*x) + (2*x*y) + (y*y)"
proof -
have "x*y + y*x = x*y + x*y" using mult_commute by simp
also have "... = (x+x)*y" using distrib_right by simp
finally have xy: "x*y + y*x = 2*x*y" using mult_2 by auto
have "sqr (x+y) = x*(x+y) + y*(x+y)" using distrib_right by auto
also have "... = x*x + x*y + y*x + y*y" using distrib_left add_assoc by auto
finally have "sqr (x+y) = (sqr x) + x*y + y*x + (sqr y)"
using distrib_left add_assoc by auto
thus ?thesis using xy add_assoc by auto
qed
lemma lemQuadraticGEZero:
assumes "∀ x. a*(sqr x) + b*x + c ≥ 0"
and "a > 0"
shows "(sqr b) ≤ 4*a*c"
proof -
{ fix x :: "'a"
have "a * sqr (x + (b/(2*a))) = a * ((sqr x) + 2*(b/(2*a))*x + (sqr (b/(2*a))))"
using lemSqrSum[of "x" "(b/(2*a))"] mult_assoc
mult_commute[of "x" "(b/(2*a))"]
by auto
hence 1: "a * sqr (x + (b/(2*a)))
= (a * (sqr x)) + (a*(2*(b/(2*a))*x)) + (a * sqr (b/(2*a)))"
using distrib_left by auto
have "a*(2*(b/(2*a))*x) = b*x" using mult_assoc assms(2) by simp
hence 2: "a * sqr (x + (b/(2*a))) = a*(sqr x) + (b*x) + (a * sqr (b/(2*a)))"
using 1 by auto
have "(a * sqr (b/(2*a))) = c + ((a * sqr (b/(2*a))) - c)"
using add_commute diff_add_cancel by auto
hence "(a * sqr (x + (b/(2*a))))
= (a*(sqr x) + (b*x) + c) + ((a * sqr (b/(2*a))) - c)" using 2 add_assoc by auto
hence 3: "(a * sqr (x + (b/(2*a)))) ≥ ((a * sqr (b/(2*a))) - c)"
using assms(1) by auto
}
hence "∀ x . (a * sqr (x + (b/(2*a)))) ≥ ((a * sqr (b/(2*a))) - c)"
by auto
hence "(a * sqr ((-b/(2*a)) + (b/(2*a)))) ≥ ((a * sqr (b/(2*a))) - c)" by fast
hence "((a * sqr (b/(2*a))) - c) ≤ 0" by simp
hence "4*a*((a * sqr (b/(2*a))) - c) ≤ 0"
using local.mult_le_0_iff assms(2) by auto
hence "4*a*((a * sqr (b/(2*a)))) - 4*a*c ≤ 0"
using right_diff_distrib mult_assoc by auto
hence 4: "4*a*((a * sqr (b/(2*a)))) ≤ 4*a*c" by simp
have "sqr (b/(2*a)) = (sqr b)/(4*a*a)"
using mult_assoc mult_commute by simp
hence "4*a*((a * sqr (b/(2*a)))) = 4*a*((a * (sqr b)/(4*a*a)))" by auto
hence "4*a*((a * sqr (b/(2*a)))) = (4*a*a)*(sqr b)/(4*a*a)"
using mult_commute by auto
hence "4*a*((a * sqr (b/(2*a)))) = (sqr b)"
using assms(2) by simp
thus ?thesis using 4 by auto
qed
lemma lemSquareExistsAbove:
shows "∃ x > 0 . (sqr x) > y"
proof -
have cases: "(y ≤ 0) ∨ (y > 0)" by auto
have one: "1 ≥ 0" by simp
have onestrict: "0 < 1" by simp
{ assume yle0: "y ≤ 0"
hence "y < sqr 1" using yle0 le_less_trans by simp
hence ?thesis using onestrict by fast
}
hence case1: "(y ≤ 0) ⟶ ?thesis" by auto
{ assume ygt0: "y > 0"
{ assume ylt1: "y < 1"
hence "sqr y < y" using ygt0 mult_strict_left_mono[of "y" "1"] by auto
hence "sqr y < sqr 1" using ylt1 by simp
hence "y < 1" using ygt0 lemSqrOrderedStrict[of "1" "y"] by auto
hence "y < sqr 1" by simp
hence "?thesis" using onestrict by best
}
hence a: "(y < 1) ⟶ ?thesis" by auto
{ assume "y = 1"
hence b1: "y < sqr 2" by simp
have "2 > 0" by simp
hence "?thesis" using b1 by fast
}
hence b: "(y = 1) ⟶ ?thesis" by auto
{ assume ygt1: "y > 1"
hence yge1: "y ≥ 1" by simp
have yge0: "y ≥ 0" using ygt0 by simp
have "y ≤ y" by simp
hence "sqr y > y*1" using lemMultPosLT ygt0 ygt1 by blast
hence "sqr y > y" by simp
hence "?thesis" using ygt0 by bestsimp
}
hence "(y > 1) ⟶ ?thesis" by simp
hence "((y<1)∨(y=1)∨(y>1)) ⟶ ?thesis" using a b by auto
hence ?thesis by fastforce
}
hence ypos: "(y > 0) ⟶ ?thesis" by auto
thus ?thesis using cases case1 by auto
qed
lemma lemSmallSquares:
assumes "x > 0"
shows "∃ y > 0. (sqr y < x)"
proof -
have invpos: "1/x > 0" using assms(1) by auto
then obtain z where z: "(z > 0) ∧ ((sqr z) > (1/x))"
using lemSquareExistsAbove by auto
define y where y: "y = 1/z"
hence ypos: "y > 0" using z by auto
have 1: "1/(sqr z) < 1/(1/x)" using z invpos
by (meson local.divide_strict_left_mono
local.mult_pos_pos local.zero_less_one)
hence "(sqr y) < x" using z y by simp
thus ?thesis using ypos by auto
qed
lemma lemSqrLT1:
assumes "0 < x < 1"
shows "0 < (sqr x) < x"
using assms lemMultPosLT1[of "x" "x"] by auto
lemma lemReducedBound:
assumes "x > 0"
shows "∃ y > 0 . (y < x) ∧ (sqr y < y) ∧ (y < 1)"
proof -
have x2: "x > x/2"
using assms lemSumOfTwoHalves[of "x"] add_strict_left_mono[of "0" "x/2" "x/2"]
by auto
have x2pos: "x/2 > 0" using assms by simp
define y where "y = min (x/2) (1/2)"
hence y: "(y ≤ x/2) ∧ (y ≤ 1/2) ∧ (y > 0)" using x2pos by auto
have yltx: "y < x" using y x2 le_less_trans by auto
have ylt1: "y < 1" using y le_less_trans by auto
hence "sqr y < y" using lemSqrLT1 y by simp
thus ?thesis using yltx ylt1 y by auto
qed
end
end