Theory Rational_FPS_Solver
section ‹Solver for rational formal power series›
theory Rational_FPS_Solver
imports
Complex_Main
Pochhammer_Polynomials
Partial_Fraction_Decomposition
Factorizations
"HOL-Computational_Algebra.Field_as_Ring"
begin
text ‹
We can determine the $k$-th coefficient of an FPS of the form $d/(1-cX)^n$, which is
an important step in solving linear recurrences. The $k$-th coefficient of such an FPS is always
of the form $p(k) c^k$ where $p$ is the following polynomial:
›
definition inverse_irred_power_poly :: "'a :: field_char_0 ⇒ nat ⇒ 'a poly" where
"inverse_irred_power_poly d n =
Poly [(d * of_nat (stirling n (k+1))) / (fact (n - 1)). k ← [0..<n]]"
lemma one_minus_const_fps_X_neg_power'':
fixes c :: "'a :: field_char_0"
assumes n: "n > 0"
shows "fps_const d / ((1 - fps_const (c :: 'a :: field_char_0) * fps_X) ^ n) =
Abs_fps (λk. poly (inverse_irred_power_poly d n) (of_nat k) * c^k)" (is "?lhs = ?rhs")
proof (rule fps_ext)
include fps_syntax
fix k :: nat
let ?p = "smult (d / (fact (n - 1))) (pcompose (pochhammer_poly (n - 1)) [:1,1:])"
from n have "?lhs = fps_const d * inverse ((1 - fps_const c * fps_X) ^ n)"
by (subst fps_divide_unit) auto
also have "inverse ((1 - fps_const c * fps_X) ^ n) =
Abs_fps (λk. of_nat ((n + k - 1) choose k) * c^k)"
by (intro one_minus_const_fps_X_neg_power' n)
also have "(fps_const d * …) $ k = d * of_nat ((n + k - 1) choose k) * c^k" by simp
also from n have "(n + k - 1 choose k) = (n + k - 1 choose (n - 1))"
by (subst binomial_symmetric) simp_all
also from n have "of_nat … = (pochhammer (of_nat k + 1) (n - 1) / fact (n - 1) :: 'a)"
by (simp_all add: binomial_gbinomial gbinomial_pochhammer' of_nat_diff)
also have "d * … = poly ?p (of_nat k)"
by (simp add: divide_inverse eval_pochhammer_poly poly_pcompose add_ac)
also {
from assms have "pCons 0 (pcompose (pochhammer_poly (n-1)) [:1,1::'a:]) = pochhammer_poly n"
by (subst pochhammer_poly_Suc' [symmetric]) simp
also from assms have "… = pCons 0 (Poly [of_nat (stirling n (k+1)). k ← [0..<Suc n]])"
unfolding pochhammer_poly_def
by (auto simp add: poly_eq_iff nth_default_def coeff_pCons
split: nat.split simp del: upt_Suc )
finally have "pcompose (pochhammer_poly (n-1)) [:1,1::'a:] =
Poly [of_nat (stirling n (k+1)). k ← [0..<Suc n]]" by simp
}
also have "smult (d / fact (n - 1)) (Poly [of_nat (stirling n (k+1)). k ← [0..<Suc n]]) =
inverse_irred_power_poly d n"
by (auto simp: poly_eq_iff inverse_irred_power_poly_def nth_default_def)
also have "poly … (of_nat k) * c ^ k = ?rhs $ k" by simp
finally show "?lhs $ k = ?rhs $ k" .
qed
lemma inverse_irred_power_poly_code [code abstract]:
"coeffs (inverse_irred_power_poly d n) =
(if n = 0 ∨ d = 0 then [] else
let e = d / (fact (n - 1))
in [e * of_nat x. x ← tl (stirling_row n)])"
proof (cases "n = 0 ∨ d = 0")
case False
define e where "e = d / (fact (n - 1))"
from False have "coeffs (inverse_irred_power_poly d n) =
[e * of_nat (stirling n (k+1)). k ← [0..<n]]"
by (auto simp: inverse_irred_power_poly_def Let_def divide_inverse mult_ac last_map
stirling_row_def map_tl [symmetric] tl_upt e_def no_trailing_unfold)
also have "… = [e * of_nat x. x ← tl (stirling_row n)]"
by (simp add: stirling_row_def map_tl [symmetric] o_def tl_upt
map_Suc_upt [symmetric] del: upt_Suc)
finally show ?thesis using False by (simp add: Let_def e_def)
qed (auto simp: inverse_irred_power_poly_def)
lemma solve_rat_fps_aux:
fixes p :: "'a :: {field_char_0,field_gcd} poly" and cs :: "('a × nat) list"
assumes distinct: "distinct (map fst cs)"
assumes azs: "(a, zs) = poly_pfd_simple p cs"
assumes nz: "0 ∉ fst ` set cs"
shows "fps_of_poly p / fps_of_poly (∏(c,n)←cs. [:1,-c:]^Suc n) =
Abs_fps (λk. coeff a k + (∑i<length cs. poly (∑j≤snd (cs ! i).
(inverse_irred_power_poly (zs ! i ! j) (snd (cs ! i)+1 - j)))
(of_nat k) * (fst (cs ! i)) ^ k))" (is "_ = ?rhs")
proof -
interpret pfd_homomorphism "fps_of_poly :: 'a poly ⇒ 'a fps"
by standard (auto simp: fps_of_poly_add fps_of_poly_mult)
from distinct have distinct': "(a, b1) ∈ set cs ⟹
(a, b2) ∈ set cs ⟹ b1 = b2" for a b1 b2
by (metis (no_types, opaque_lifting) Some_eq_map_of_iff image_set in_set_zipE insert_iff list.simps(15) map_of_Cons_code(2) map_of_SomeD nz snd_conv)
from nz have nz': "(0, b) ∉ set cs" for b
by (auto simp add: image_iff)
define n where "n = length cs"
let ?g = "λ(c, n). [:1, - c:] ^ Suc n"
have "inj_on ?g (set cs)"
proof
fix x y
assume "x ∈ set cs" "y ∈ set cs" "?g x = ?g y"
moreover obtain c1 n1 c2 n2 where [simp]: "x = (c1, n1)" "y = (c2, n2)"
by (cases x, cases y)
ultimately have in_cs: "(c1, n1) ∈ set cs"
"(c2, n2) ∈ set cs"
and eq: "[:1, - c1:] ^ Suc n1 = [:1, - c2:] ^ Suc n2"
by simp_all
with nz have [simp]: "c1 ≠ 0" "c2 ≠ 0"
by (auto simp add: image_iff)
have "Suc n1 = degree ([:1, - c1:] ^ Suc n1)"
by (simp add: degree_power_eq del: power_Suc)
also have "… = degree ([:1, - c2:] ^ Suc n2)"
using eq by simp
also have "… = Suc n2"
by (simp add: degree_power_eq del: power_Suc)
finally have "n1 = n2" by simp
then have "0 = poly ([:1, - c1:] ^ Suc n1) (1 / c1)"
by simp
also have "… = poly ([:1, - c2:] ^ Suc n2) (1 / c1)"
using eq by simp
finally show "x = y" using ‹n1 = n2›
by (auto simp: field_simps)
qed
with distinct have distinct': "distinct (map ?g cs)"
by (simp add: distinct_map del: power_Suc)
from nz' distinct have coprime: "pairwise coprime (?g ` set cs)"
by (auto intro!: pairwise_imageI coprime_linear_poly' simp add: eq_key_imp_eq_value
simp del: power_Suc)
have [simp]: "length zs = n"
using assms by (simp add: poly_pfd_simple_def n_def split: if_split_asm)
have [simp]: "i < length cs ⟹ length (zs!i) = snd (cs!i)+1" for i
using assms by (simp add: poly_pfd_simple_def Let_def case_prod_unfold split: if_split_asm)
let ?f = "λ(c, n). ([:1,-c:], n)"
let ?cs' = "map ?f cs"
have "fps_of_poly (fst (poly_pfd_simple p cs)) +
(∑i<length ?cs'. ∑j≤snd (?cs' ! i).
from_decomp (map (map (λc. [:c:])) (snd (poly_pfd_simple p cs)) ! i ! j)
(fst (?cs' ! i)) (snd (?cs' ! i)+1 - j)) =
fps_of_poly p / fps_of_poly (∏(x, n)←?cs'. x ^ Suc n)"
(is "?A = ?B") using nz distinct' coprime
by (intro partial_fraction_decomposition poly_pfd_simple)
(force simp: o_def case_prod_unfold simp del: power_Suc)+
note this [symmetric]
also from azs [symmetric]
have "?A = fps_of_poly a + (∑i<n. ∑j≤snd (cs ! i). from_decomp
(map (map (λc. [:c:])) zs ! i ! j) [:1,-fst (cs ! i):] (snd (cs ! i)+1 - j))"
(is "_ = _ + ?S") by (simp add: case_prod_unfold Let_def n_def)
also have "?S = (∑i<length cs. ∑j≤snd (cs ! i). fps_const (zs ! i ! j) /
((1 - fps_const (fst (cs!i))*fps_X) ^ (snd (cs!i)+1 - j)))"
by (intro sum.cong refl)
(auto simp: from_decomp_def map_nth n_def fps_of_poly_linear' fps_of_poly_simps
fps_const_neg [symmetric] mult_ac simp del: fps_const_neg)
also have "… = (∑i<length cs. ∑j≤snd (cs ! i) .
Abs_fps (λk. poly (inverse_irred_power_poly (zs ! i ! j)
(snd (cs ! i)+1 - j)) (of_nat k) * (fst (cs ! i)) ^ k))"
using nz by (intro sum.cong refl one_minus_const_fps_X_neg_power'') auto
also have "fps_of_poly a + … = ?rhs"
by (intro fps_ext) (simp_all add: sum_distrib_right fps_sum_nth poly_sum)
finally show ?thesis by (simp add: o_def case_prod_unfold)
qed
definition solve_factored_ratfps ::
"('a :: {field_char_0,field_gcd}) poly ⇒ ('a × nat) list ⇒ 'a poly × ('a poly × 'a) list" where
"solve_factored_ratfps p cs = (let n = length cs in case poly_pfd_simple p cs of (a, zs) ⇒
(a, zip_with (λzs (c,n). ((∑(z,j) ← zip zs [0..<Suc n].
inverse_irred_power_poly z (n + 1 - j)), c)) zs cs))"
lemma length_snd_poly_pfd_simple [simp]: "length (snd (poly_pfd_simple p cs)) = length cs"
by (simp add: poly_pfd_simple_def)
lemma length_nth_snd_poly_pfd_simple [simp]:
"i < length cs ⟹ length (snd (poly_pfd_simple p cs) ! i) = snd (cs!i) + 1"
by (auto simp: poly_pfd_simple_def case_prod_unfold Let_def)
lemma solve_factored_ratfps_roots:
"map snd (snd (solve_factored_ratfps p cs)) = map fst cs"
by (rule nth_equalityI)
(simp_all add: solve_factored_ratfps_def poly_pfd_simple case_prod_unfold Let_def
zip_with_altdef o_def)
definition interp_ratfps_solution where
"interp_ratfps_solution = (λ(p,cs) n. coeff p n + (∑(q,c)←cs. poly q (of_nat n) * c ^ n))"
lemma solve_factored_ratfps:
fixes p :: "'a :: {field_char_0,field_gcd} poly" and cs :: "('a × nat) list"
assumes distinct: "distinct (map fst cs)"
assumes nz: "0 ∉ fst ` set cs"
shows "fps_of_poly p / fps_of_poly (∏(c,n)←cs. [:1,-c:]^Suc n) =
Abs_fps (interp_ratfps_solution (solve_factored_ratfps p cs))" (is "?lhs = ?rhs")
proof -
obtain a zs where azs: "(a, zs) = solve_factored_ratfps p cs"
using prod.exhaust by metis
from azs have a: "a = fst (poly_pfd_simple p cs)"
by (simp add: solve_factored_ratfps_def Let_def case_prod_unfold)
define zs' where "zs' = snd (poly_pfd_simple p cs)"
with a have azs': "(a, zs') = poly_pfd_simple p cs" by simp
from azs have zs: "zs = snd (solve_factored_ratfps p cs)"
by (auto simp add: snd_def split: prod.split)
have "?lhs = Abs_fps (λk. coeff a k + (∑i<length cs. poly (∑j≤snd (cs ! i).
inverse_irred_power_poly (zs' ! i ! j) (snd (cs ! i)+1 - j))
(of_nat k) * (fst (cs ! i)) ^ k))"
by (rule solve_rat_fps_aux[OF distinct azs' nz])
also from azs have "… = ?rhs" unfolding interp_ratfps_solution_def
by (auto simp: a zs solve_factored_ratfps_def Let_def case_prod_unfold zip_altdef
zip_with_altdef' sum_list_sum_nth atLeast0LessThan zs'_def lessThan_Suc_atMost
intro!: fps_ext sum.cong simp del: upt_Suc)
finally show ?thesis .
qed
definition solve_factored_ratfps' where
"solve_factored_ratfps' = (λp (a,cs). solve_factored_ratfps (smult (inverse a) p) cs)"
lemma solve_factored_ratfps':
assumes "is_alt_factorization_of fctrs q" "q ≠ 0"
shows "Abs_fps (interp_ratfps_solution (solve_factored_ratfps' p fctrs)) =
fps_of_poly p / fps_of_poly q"
proof -
from assms have q: "q = interp_alt_factorization fctrs"
by (simp add: is_alt_factorization_of_def)
from assms(2) have nz: "fst fctrs ≠ 0"
by (subst (asm) q) (auto simp: interp_alt_factorization_def case_prod_unfold)
note q
also from nz have "coeff (interp_alt_factorization fctrs) 0 ≠ 0"
by (auto simp: interp_alt_factorization_def case_prod_unfold coeff_0_prod_list
o_def coeff_0_power prod_list_zero_iff)
finally have "coeff q 0 ≠ 0" .
obtain a cs where fctrs: "fctrs = (a, cs)" by (cases fctrs) simp_all
obtain b zs where sol: "solve_factored_ratfps' p fctrs = (b, zs)" using prod.exhaust by metis
from assms have [simp]: "a ≠ 0"
by (auto simp: is_alt_factorization_of_def interp_alt_factorization_def fctrs)
have "fps_of_poly p / fps_of_poly (smult a (∏(c, n)←cs. [:1, - c:] ^ Suc n)) =
fps_of_poly p / (fps_const a * fps_of_poly (∏(c, n)←cs. [:1, - c:] ^ Suc n))"
by (simp_all add: fps_of_poly_smult case_prod_unfold del: power_Suc)
also have "… = fps_of_poly p / fps_const a / fps_of_poly (∏(c, n)←cs. [:1, - c:] ^ Suc n)"
by (subst is_unit_div_mult2_eq)
(auto simp: coeff_0_power coeff_0_prod_list prod_list_zero_iff)
also have "fps_of_poly p / fps_const a = fps_of_poly (smult (inverse a) p)"
by (simp add: fps_const_inverse fps_divide_unit)
also from assms have "smult a (∏(c, n)←cs. [:1, - c:] ^ Suc n) = q"
by (simp add: is_alt_factorization_of_def interp_alt_factorization_def fctrs del: power_Suc)
also have "fps_of_poly (smult (inverse a) p) /
fps_of_poly (∏(c, n)←cs. [:1, - c:] ^ Suc n) =
Abs_fps (interp_ratfps_solution (solve_factored_ratfps (smult (inverse a) p) cs))"
(is "?lhs = _") using assms
by (intro solve_factored_ratfps)
(simp_all add: is_alt_factorization_of_def fctrs solve_factored_ratfps'_def)
also have "… = Abs_fps (interp_ratfps_solution (solve_factored_ratfps' p fctrs))"
by (simp add: solve_factored_ratfps'_def fctrs)
finally show ?thesis ..
qed
lemma degree_Poly_eq:
assumes "xs = [] ∨ last xs ≠ 0"
shows "degree (Poly xs) = length xs - 1"
proof -
from assms consider "xs = []" | "xs ≠ []" "last xs ≠ 0" by blast
thus ?thesis
proof cases
assume "last xs ≠ 0" "xs ≠ []"
hence "no_trailing ((=) 0) xs" by (auto simp: no_trailing_unfold)
thus ?thesis by (simp add: degree_eq_length_coeffs)
qed auto
qed
lemma degree_Poly': "degree (Poly xs) ≤ length xs - 1"
using length_strip_while_le[of "(=) 0" xs] by (simp add: degree_eq_length_coeffs)
lemma degree_inverse_irred_power_poly_le:
"degree (inverse_irred_power_poly c n) ≤ n - 1"
by (auto simp: inverse_irred_power_poly_def intro: order.trans[OF degree_Poly'])
lemma degree_inverse_irred_power_poly:
assumes "c ≠ 0"
shows "degree (inverse_irred_power_poly c n) = n - 1"
unfolding inverse_irred_power_poly_def using assms
by (subst degree_Poly_eq) (auto simp: last_conv_nth)
lemma reflect_poly_0_iff [simp]: "reflect_poly p = 0 ⟷ p = 0"
using coeff_0_reflect_poly_0_iff[of p] by fastforce
lemma degree_sum_list_le: "(⋀p. p ∈ set ps ⟹ degree p ≤ T) ⟹ degree (sum_list ps) ≤ T"
by (induction ps) (auto intro: degree_add_le)
theorem ratfps_closed_form_exists:
fixes q :: "complex poly"
assumes nz: "coeff q 0 ≠ 0"
defines "q' ≡ reflect_poly q"
obtains r rs
where "⋀n. fps_nth (fps_of_poly p / fps_of_poly q) n =
coeff r n + (∑c | poly q' c = 0. poly (rs c) (of_nat n) * c ^ n)"
and "⋀z. poly q' z = 0 ⟹ degree (rs z) ≤ order z q' - 1"
proof -
from assms have nz': "q ≠ 0" by auto
from complex_alt_factorization_exists [OF nz]
obtain fctrs where fctrs: "is_alt_factorization_of fctrs q" ..
with nz have fctrs': "is_factorization_of fctrs q'" unfolding q'_def
by (rule reflect_factorization')
define r where "r = fst (solve_factored_ratfps' p fctrs)"
define ts where "ts = snd (solve_factored_ratfps' p fctrs)"
define rs where "rs = the ∘ map_of (map (λ(x,y). (y,x)) ts)"
from nz' have "q' ≠ 0" by (simp add: q'_def)
hence roots: "{z. poly q' z = 0} = set (map fst (snd fctrs))"
using is_factorization_of_roots [of "fst fctrs" "snd fctrs" q'] fctrs' by simp
have rs: "rs c = r" if "(r, c) ∈ set ts" for c r
proof -
have "map_of (map (λ(x,y). (y, x)) (snd (solve_factored_ratfps' p fctrs))) c = Some r"
using that fctrs
by (intro map_of_is_SomeI)
(force simp: o_def case_prod_unfold solve_factored_ratfps'_def ts_def
solve_factored_ratfps_roots is_alt_factorization_of_def)+
thus ?thesis by (simp add: rs_def ts_def)
qed
have [simp]: "length ts = length (snd fctrs)"
by (auto simp: ts_def solve_factored_ratfps'_def case_prod_unfold solve_factored_ratfps_def)
{
fix n :: nat
have "fps_of_poly p / fps_of_poly q =
Abs_fps (interp_ratfps_solution (solve_factored_ratfps' p fctrs))"
using solve_factored_ratfps' [OF fctrs nz'] ..
also have "fps_nth … n = interp_ratfps_solution (solve_factored_ratfps' p fctrs) n"
by simp
also have "… = coeff r n + (∑p←snd (solve_factored_ratfps' p fctrs).
poly (fst p) (of_nat n) * snd p ^ n)" (is "_ = _ + ?A")
unfolding interp_ratfps_solution_def case_prod_unfold r_def by simp
also have "?A = (∑p←ts. poly (rs (snd p)) (of_nat n) * snd p ^ n)"
by (intro arg_cong[OF map_cong] refl) (auto simp: rs ts_def)
also have "… = (∑c←map snd ts.
poly (rs c) (of_nat n) * c ^ n)" by (simp add: o_def)
also have "map snd ts = map fst (snd fctrs)"
unfolding solve_factored_ratfps'_def case_prod_unfold ts_def
by (rule solve_factored_ratfps_roots)
also have "(∑c←…. poly (rs c) (of_nat n) * c ^ n) =
(∑c | poly q' c = 0. poly (rs c) (of_nat n) * c ^ n)" unfolding roots
using fctrs by (intro sum_list_distinct_conv_sum_set) (auto simp: is_alt_factorization_of_def)
finally have "fps_nth (fps_of_poly p / fps_of_poly q) n =
coeff r n + (∑c∈{z. poly q' z = 0}. poly (rs c) (of_nat n) * c ^ n)" .
} moreover {
fix z assume "poly q' z = 0"
hence "z ∈ set (map fst (snd fctrs))" using roots by blast
then obtain i where i: "i < length (snd fctrs)" and [simp]: "z = fst (snd fctrs ! i)"
by (auto simp: set_conv_nth)
from i have "(fst (ts ! i), snd (ts ! i)) ∈ set ts"
by (auto simp: set_conv_nth)
also from i have "snd (ts ! i) = z"
by (simp add: ts_def solve_factored_ratfps'_def case_prod_unfold solve_factored_ratfps_def)
finally have "rs z = fst (ts ! i)" by (intro rs) auto
also have "… = (∑p←zip (snd (poly_pfd_simple (smult (inverse (fst fctrs)) p) (snd fctrs)) ! i)
[0..<Suc (snd (snd fctrs ! i))].
inverse_irred_power_poly (fst p) (Suc (snd (snd fctrs ! i)) - snd p))"
using i by (auto simp: ts_def solve_factored_ratfps'_def solve_factored_ratfps_def o_def
case_prod_unfold Let_def simp del: upt_Suc power_Suc)
also have "degree … ≤ snd (snd fctrs ! i)"
by (intro degree_sum_list_le)
(auto intro!: order.trans [OF degree_inverse_irred_power_poly_le])
also have "order z q' = Suc …"
using nz' fctrs' i
by (intro is_factorization_of_order[of q' "fst fctrs" "snd fctrs"]) (auto simp: q'_def)
hence "snd (snd fctrs ! i) = order z q' - 1" by simp
finally have "degree (rs z) ≤ …" .
}
ultimately show ?thesis
using that[of r rs] by blast
qed
end